3/4r^2-5/7r-2=0

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Solution for 3/4r^2-5/7r-2=0 equation: 


r in (-oo:+oo)

(3/4)*r^2-((5/7)*r)-2 = 0

(3/4)*r^2+(-5/7)*r-2 = 0

3/4*r^2-5/7*r-2 = 0

DELTA = (-5/7)^2-(-2*3/4*4)

DELTA = 319/49

DELTA > 0

r = ((319/49)^(1/2)+5/7)/(3/4*2) or r = (5/7-(319/49)^(1/2))/(3/4*2)

r = 2/3*((319/49)^(1/2)+5/7) or r = 2/3*(5/7-(319/49)^(1/2))

r in { 2/3*(5/7-(319/49)^(1/2)), 2/3*((319/49)^(1/2)+5/7) }

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